Given: x1=4 y1=3 x2=7 y2=0
Distance Formula: d = √(x2 – x1)2 + (y2 – y1)2
d = √(7 – 4)2 + (0 – 3)2
d = √(3)2 + (-3)2
d = √9 + 9
d = √18
d = √9 * √2
d = 3√2 = 4.242641
The distance between (4, 3) and (7, 0)
The solution above and other related solutions were provided by the Distance Between Two Points Application.
