Missing lengths of a 45°-45°-90° Special Right Triangle given Hypotenuse length = 6

Leg lengths of a 45°-45°-90° Special Right Triangle are equal
Leg lengths =
Hypotenuse length/2

Leg lengths =
6/2

Rationalize to remove the radical from the denominator:
Leg lengths =
6 * √2/2 * √2

Leg lengths =
6√2/2

Leg lengths = 3√2 = 4.242640687119

The solution above and all other related solutions were provided by the 45°-45°-90° Special Right Triangle Application