Missing lengths of a 45°-45°-90° Special Right Triangle given Hypotenuse length = 5

Leg lengths of a 45°-45°-90° Special Right Triangle are equal
Leg lengths =
Hypotenuse length/2

Leg lengths =
5/2

Rationalize to remove the radical from the denominator:
Leg lengths =
5 * √2/2 * √2

Leg lengths =
5√2/2
= 2.5√2 = 3.535533905933

The solution above and all other related solutions were provided by the 45°-45°-90° Special Right Triangle Application