Missing lengths of a 45°-45°-90° Special Right Triangle given Hypotenuse length = 16

Leg lengths of a 45°-45°-90° Special Right Triangle are equal
Leg lengths =
Hypotenuse length/2

Leg lengths =
16/2

Rationalize to remove the radical from the denominator:
Leg lengths =
16 * √2/2 * √2

Leg lengths =
16√2/2

Leg lengths = 8√2 = 11.313708498985

The solution above and all other related solutions were provided by the 45°-45°-90° Special Right Triangle Application