- Determine the two consecutive multiples of 1,000 that bracket 9,328
- 9,328 is between 9,000 and 10,000
- 9,500 is the midpoint between 9,000 and 10,000
- As illustrated on the number line, 9,328 is less than the midpoint (9,500)
- Therefore, 9,328 rounded to the nearest thousand = 9,000
