Given: x1=1 y1=3 x2=5 y2=7
Distance Formula: d = √(x2 – x1)2 + (y2 – y1)2
d = √(5 – 1)2 + (7 – 3)2
d = √(4)2 + (4)2
d = √16 + 16
d = √32
d = √16 * √2
d = 4√2 = 5.656854
The distance between (1, 3) and (5, 7)
The solution above and other related solutions were provided by the Distance Between Two Points Application.
