Missing lengths of a 45°-45°-90° Special Right Triangle given Hypotenuse length = √6

Leg lengths of a 45°-45°-90° Special Right Triangle are equal
Leg lengths =
Hypotenuse length/√2

Leg lengths =
√6/√2

Since 6 is divisible by 2, apply the quotient rule for radicals:
Leg lengths =
√6/√2
=
√
6/2

Leg lengths = √3 = 1.732050807569

The solution above and all other related solutions were provided by the 45°-45°-90° Special Right Triangle Application.